X+4=x^2-2x-20

Solution for X+4=x^2-2x-20 equation:

X+4=X^2-2X-20

We move all terms to the left:

X+4-(X^2-2X-20)=0

We get rid of parentheses

-X^2+X+2X+20+4=0

We add all the numbers together, and all the variables

-1X^2+3X+24=0

a = -1; b = 3; c = +24;
Δ = b2-4ac
Δ = 32-4·(-1)·24
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{105}}{2*-1}=\frac{-3-\sqrt{105}}{-2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{105}}{2*-1}=\frac{-3+\sqrt{105}}{-2}
$